Review

, Volume: 6( 1)

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Model of Nuclear

*Correspondence:

Buchakchiiskiy FF, University of St.Gagarin Severodonetsk, Ukraine, Tel: 33662922853; E-mail: ffbuchak@gmail.com

Abstract

It is assumed that basis for formutation of all nuclei is a nucleus of helium. All subsequent nuclei of elements consist of chain of nuclei of helium. They are constrained inter se to binding energy equal energy of separation of nucleus of helium. The chain of nuclei of helium coagulates in a ball.

Keywords

Nuclonous; Helium; Electrolysis; Calcium; Electrode

Introduction

It is known that the number of nuclonous in a nuclei is multiple four plays a large role at determination of properties of nucleus.

Foremost at the nuclei of containing an even number protons and neutrons spin of nucleus equal to the zero. To this group of elements belong helium ,carbon , oxygen. Because the nucleus of helium is the simplest, then it serves as basis for the constriction of all anther nuclei. We will consider the chart of formation of nuclei. We will bild a chart for calcium. For this purpose we will define the chain of values of energy of separation of nucleus of helium [1-10].

Experimental

Energy of separation

Let us now construct a chain of ten helium nuclei to obtain core the calcium

Results and Discussion

In table (picture 1) is presented the variant all even nuclei, since the nucleus of helium , ending uranium

Gonrned, used for the constraction of this table following:

Elements consist of chain of nuclei of helium or isotopes of helium, that enter into co-operation. The value of this cooperation is equal to energy of separation of nucleus of helium or isotope of helium from an element.

This energy links the chain of nuclei.

The constructon of nuclei with even number is begun with nucleus of helium, with an odd number a construction is begun with deuterium or tritium Therefore there are two chains of nuclei.

In lines the numbers against the name elements stand mass of isotopes.

For example:

Element appears from a nucleus of helium addition of another nucleus,

or addition of isotope of helium,

For carbon is brought four isotope

The chart of formation of there isotopes is such,

Another example of formation of isotopes of calcium,

On a picture 2 a chain is presented from the isotope of helium to uranium ,This chain is also distinguished in the table of formation of nucleus (picture 1). Criterion of choice of method of formation of nucleus is a value of energy of separation of element. We find the value of energy of separation (ES_α) for all elements from beryllium to uranium. If this value is positive, then of nucleus of helium becomes formative, if this value becomes negative then the isotope of helium becomes formative.

In a right side Figures 1-4 the value of energy of separation (ES_α) and isotope helium is presented from Coo responding clements (Table 1).

Table 1: In a right side pictare 2 the value of energy of separation (ESα) and isotope helium is presented from COO responding clements.

Conclusion

Chain of nuclei convolves in a ball. Similar below. Division of nucleus of uranium on two parts making 2/3 basic nucleus devides the break of chain near a nucleus where ESα goes across through a Zero. Placing of the superfluous no included in a?-nuclei neutrons (n=A-2Z).

Appendix

To find a radius, where potential energy of coulomb forces is equal to 10 MeV.

q=l=1,6*10^-19 Cl

1 MeV=1,6*10^-13 gl

k=9*10⁹

Wc=10 Mev=1.6 *10^-12 gl

1 MeV=1,6*10^-13 gl

Z₁=2 Z₂=50|

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